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Share Question Copy Link. Need the answer? Boron trifluoride BF 3 has a boron atom with three outer-shell electrons in its normal or ground state, as well as three fluorine atoms, each with seven outer electrons.

One of the three boron electrons is unpaired in the ground state. In order to explain the bonding, the 2s orbital and two of the 2p orbitals called sp 2 hybrids hybridize; one empty p-orbital remains.

Ethene C 2 H 4 has a double bond between the carbons. In this case, carbon will sp 2 hybridize; in sp 2 hybridization, the 2s orbital mixes with only two of the three available 2p orbitals, forming a total of three sp hybrid orbitals with one p-orbital remaining.

The three hybridized orbitals explain the three sigma bonds that each carbon forms.



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